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9q^2-18q-72=0
a = 9; b = -18; c = -72;
Δ = b2-4ac
Δ = -182-4·9·(-72)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-54}{2*9}=\frac{-36}{18} =-2 $$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+54}{2*9}=\frac{72}{18} =4 $
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